-10b+b=-10(b-4)-29-2(b+2)

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Solution for -10b+b=-10(b-4)-29-2(b+2) equation: 



-10b+b=-10(b-4)-29-2(b+2)

We move all terms to the left:

-10b+b-(-10(b-4)-29-2(b+2))=0

We add all the numbers together, and all the variables

-9b-(-10(b-4)-29-2(b+2))=0



We calculate terms in parentheses: -(-10(b-4)-29-2(b+2)), so:

-10(b-4)-29-2(b+2)

determiningTheFunctionDomain
-10(b-4)-2(b+2)-29

We multiply parentheses

-10b-2b+40-4-29

We add all the numbers together, and all the variables

-12b+7

Back to the equation:

-(-12b+7)



We get rid of parentheses

-9b+12b-7=0

We add all the numbers together, and all the variables

3b-7=0

We move all terms containing b to the left, all other terms to the right

3b=7

b=7/3

b=2+1/3

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