-10b+6(12-2b)=4(10-5b)

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Solution for -10b+6(12-2b)=4(10-5b) equation: 



-10b+6(12-2b)=4(10-5b)

We move all terms to the left:

-10b+6(12-2b)-(4(10-5b))=0

We add all the numbers together, and all the variables

-10b+6(-2b+12)-(4(-5b+10))=0

We multiply parentheses

-10b-12b-(4(-5b+10))+72=0



We calculate terms in parentheses: -(4(-5b+10)), so:

4(-5b+10)

We multiply parentheses

-20b+40

Back to the equation:

-(-20b+40)



We add all the numbers together, and all the variables

-22b-(-20b+40)+72=0

We get rid of parentheses

-22b+20b-40+72=0

We add all the numbers together, and all the variables

-2b+32=0

We move all terms containing b to the left, all other terms to the right

-2b=-32

b=-32/-2

b=+16

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