-10a+6a=6(4-3a)+2(8a-3)

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Solution for -10a+6a=6(4-3a)+2(8a-3) equation: 



-10a+6a=6(4-3a)+2(8a-3)

We move all terms to the left:

-10a+6a-(6(4-3a)+2(8a-3))=0

We add all the numbers together, and all the variables

-10a+6a-(6(-3a+4)+2(8a-3))=0

We add all the numbers together, and all the variables

-4a-(6(-3a+4)+2(8a-3))=0



We calculate terms in parentheses: -(6(-3a+4)+2(8a-3)), so:

6(-3a+4)+2(8a-3)

We multiply parentheses

-18a+16a+24-6

We add all the numbers together, and all the variables

-2a+18

Back to the equation:

-(-2a+18)



We get rid of parentheses

-4a+2a-18=0

We add all the numbers together, and all the variables

-2a-18=0

We move all terms containing a to the left, all other terms to the right

-2a=18

a=18/-2

a=-9

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