-10=5(2x-4)x=8

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Solution for -10=5(2x-4)x=8 equation: 



-10=5(2x-4)x=8

We move all terms to the left:

-10-(5(2x-4)x)=0



We calculate terms in parentheses: -(5(2x-4)x), so:

5(2x-4)x

We multiply parentheses

10x^2-20x

Back to the equation:

-(10x^2-20x)



We get rid of parentheses

-10x^2+20x-10=0

a = -10; b = 20; c = -10;
Δ = b2-4ac
Δ = 202-4·(-10)·(-10)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{-20}=1$

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