-100x+22x2=0

Solution for -100x+22x2=0 equation:

-100x+22x^2=0

a = 22; b = -100; c = 0;
Δ = b2-4ac
Δ = -1002-4·22·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-100}{2*22}=\frac{0}{44}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+100}{2*22}=\frac{200}{44}
=4+6/11
$