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-10-8q=9-3(5q-10)
We move all terms to the left:
-10-8q-(9-3(5q-10))=0
We calculate terms in parentheses: -(9-3(5q-10)), so:We get rid of parentheses
9-3(5q-10)
determiningTheFunctionDomain -3(5q-10)+9
We multiply parentheses
-15q+30+9
We add all the numbers together, and all the variables
-15q+39
Back to the equation:
-(-15q+39)
-8q+15q-39-10=0
We add all the numbers together, and all the variables
7q-49=0
We move all terms containing q to the left, all other terms to the right
7q=49
q=49/7
q=7
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