-10-4(1+10b)=4(1+6b)-11b

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Solution for -10-4(1+10b)=4(1+6b)-11b equation: 



-10-4(1+10b)=4(1+6b)-11b

We move all terms to the left:

-10-4(1+10b)-(4(1+6b)-11b)=0

We add all the numbers together, and all the variables

-4(10b+1)-(4(6b+1)-11b)-10=0

We multiply parentheses

-40b-(4(6b+1)-11b)-4-10=0



We calculate terms in parentheses: -(4(6b+1)-11b), so:

4(6b+1)-11b

We add all the numbers together, and all the variables

-11b+4(6b+1)

We multiply parentheses

-11b+24b+4

We add all the numbers together, and all the variables

13b+4

Back to the equation:

-(13b+4)



We add all the numbers together, and all the variables

-40b-(13b+4)-14=0

We get rid of parentheses

-40b-13b-4-14=0

We add all the numbers together, and all the variables

-53b-18=0

We move all terms containing b to the left, all other terms to the right

-53b=18

b=18/-53

b=-18/53

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