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-10+2/5a=9a
We move all terms to the left:
-10+2/5a-(9a)=0
Domain of the equation: 5a!=0We add all the numbers together, and all the variables
a!=0/5
a!=0
a∈R
-9a+2/5a-10=0
We multiply all the terms by the denominator
-9a*5a-10*5a+2=0
Wy multiply elements
-45a^2-50a+2=0
a = -45; b = -50; c = +2;
Δ = b2-4ac
Δ = -502-4·(-45)·2
Δ = 2860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2860}=\sqrt{4*715}=\sqrt{4}*\sqrt{715}=2\sqrt{715}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{715}}{2*-45}=\frac{50-2\sqrt{715}}{-90} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{715}}{2*-45}=\frac{50+2\sqrt{715}}{-90} $
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