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-10+12d=2(d-3)+16
We move all terms to the left:
-10+12d-(2(d-3)+16)=0
We calculate terms in parentheses: -(2(d-3)+16), so:We get rid of parentheses
2(d-3)+16
We multiply parentheses
2d-6+16
We add all the numbers together, and all the variables
2d+10
Back to the equation:
-(2d+10)
12d-2d-10-10=0
We add all the numbers together, and all the variables
10d-20=0
We move all terms containing d to the left, all other terms to the right
10d=20
d=20/10
d=2
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