-10(y+2)+5(3y-7)=4(y-3)+8

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Solution for -10(y+2)+5(3y-7)=4(y-3)+8 equation: 



-10(y+2)+5(3y-7)=4(y-3)+8

We move all terms to the left:

-10(y+2)+5(3y-7)-(4(y-3)+8)=0

We multiply parentheses

-10y+15y-(4(y-3)+8)-20-35=0



We calculate terms in parentheses: -(4(y-3)+8), so:

4(y-3)+8

We multiply parentheses

4y-12+8

We add all the numbers together, and all the variables

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

5y-(4y-4)-55=0

We get rid of parentheses

5y-4y+4-55=0

We add all the numbers together, and all the variables

y-51=0

We move all terms containing y to the left, all other terms to the right

y=51

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