-10(3-4x)=2(6x+10

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Solution for -10(3-4x)=2(6x+10 equation: 



-10(3-4x)=2(6x+10

We move all terms to the left:

-10(3-4x)-(2(6x+10)=0

We add all the numbers together, and all the variables

-10(-4x+3)-(2(6x+10)=0

We multiply parentheses

40x-(2(6x+10)-30=0

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