-10(1+a)+9a=-11+11(9a+9)

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Solution for -10(1+a)+9a=-11+11(9a+9) equation: 



-10(1+a)+9a=-11+11(9a+9)

We move all terms to the left:

-10(1+a)+9a-(-11+11(9a+9))=0

We add all the numbers together, and all the variables

-10(a+1)+9a-(-11+11(9a+9))=0

We add all the numbers together, and all the variables

9a-10(a+1)-(-11+11(9a+9))=0

We multiply parentheses

9a-10a-(-11+11(9a+9))-10=0



We calculate terms in parentheses: -(-11+11(9a+9)), so:

-11+11(9a+9)

determiningTheFunctionDomain
11(9a+9)-11

We multiply parentheses

99a+99-11

We add all the numbers together, and all the variables

99a+88

Back to the equation:

-(99a+88)



We add all the numbers together, and all the variables

-1a-(99a+88)-10=0

We get rid of parentheses

-1a-99a-88-10=0

We add all the numbers together, and all the variables

-100a-98=0

We move all terms containing a to the left, all other terms to the right

-100a=98

a=98/-100

a=-49/50

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