-10(1+4x)+12=6(-7x-8)=+6

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Solution for -10(1+4x)+12=6(-7x-8)=+6 equation: 



-10(1+4x)+12=6(-7x-8)=+6

We move all terms to the left:

-10(1+4x)+12-(6(-7x-8))=0

We add all the numbers together, and all the variables

-10(4x+1)-(6(-7x-8))+12=0

We multiply parentheses

-40x-(6(-7x-8))-10+12=0



We calculate terms in parentheses: -(6(-7x-8)), so:

6(-7x-8)

We multiply parentheses

-42x-48

Back to the equation:

-(-42x-48)



We add all the numbers together, and all the variables

-40x-(-42x-48)+2=0

We get rid of parentheses

-40x+42x+48+2=0

We add all the numbers together, and all the variables

2x+50=0

We move all terms containing x to the left, all other terms to the right

2x=-50

x=-50/2

x=-25

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