-10(1+4x)+12=6(-7x-8)+6

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Solution for -10(1+4x)+12=6(-7x-8)+6 equation: 



-10(1+4x)+12=6(-7x-8)+6

We move all terms to the left:

-10(1+4x)+12-(6(-7x-8)+6)=0

We add all the numbers together, and all the variables

-10(4x+1)-(6(-7x-8)+6)+12=0

We multiply parentheses

-40x-(6(-7x-8)+6)-10+12=0



We calculate terms in parentheses: -(6(-7x-8)+6), so:

6(-7x-8)+6

We multiply parentheses

-42x-48+6

We add all the numbers together, and all the variables

-42x-42

Back to the equation:

-(-42x-42)



We add all the numbers together, and all the variables

-40x-(-42x-42)+2=0

We get rid of parentheses

-40x+42x+42+2=0

We add all the numbers together, and all the variables

2x+44=0

We move all terms containing x to the left, all other terms to the right

2x=-44

x=-44/2

x=-22

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