-10(1+4b)+12=6(-7b-8)+16

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Solution for -10(1+4b)+12=6(-7b-8)+16 equation: 



-10(1+4b)+12=6(-7b-8)+16

We move all terms to the left:

-10(1+4b)+12-(6(-7b-8)+16)=0

We add all the numbers together, and all the variables

-10(4b+1)-(6(-7b-8)+16)+12=0

We multiply parentheses

-40b-(6(-7b-8)+16)-10+12=0



We calculate terms in parentheses: -(6(-7b-8)+16), so:

6(-7b-8)+16

We multiply parentheses

-42b-48+16

We add all the numbers together, and all the variables

-42b-32

Back to the equation:

-(-42b-32)



We add all the numbers together, and all the variables

-40b-(-42b-32)+2=0

We get rid of parentheses

-40b+42b+32+2=0

We add all the numbers together, and all the variables

2b+34=0

We move all terms containing b to the left, all other terms to the right

2b=-34

b=-34/2

b=-17

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