-10(1+4b)+12=12(-7b-8)+6

Solution for -10(1+4b)+12=12(-7b-8)+6 equation:

-10(1+4b)+12=12(-7b-8)+6

We move all terms to the left:

-10(1+4b)+12-(12(-7b-8)+6)=0

We add all the numbers together, and all the variables

-10(4b+1)-(12(-7b-8)+6)+12=0

We multiply parentheses

-40b-(12(-7b-8)+6)-10+12=0


We calculate terms in parentheses: -(12(-7b-8)+6), so:

12(-7b-8)+6

We multiply parentheses

-84b-96+6

We add all the numbers together, and all the variables

-84b-90

Back to the equation:

-(-84b-90)


We add all the numbers together, and all the variables

-40b-(-84b-90)+2=0

We get rid of parentheses

-40b+84b+90+2=0

We add all the numbers together, and all the variables

44b+92=0

We move all terms containing b to the left, all other terms to the right

44b=-92

b=-92/44

b=-2+1/11