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-1/x+2=7/5x+10+1
We move all terms to the left:
-1/x+2-(7/5x+10+1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x+10+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
5x+1)!=-10
x∈R
-1/x-(7/5x+11)+2=0
We get rid of parentheses
-1/x-7/5x-11+2=0
We calculate fractions
(-5x)/5x^2+(-7x)/5x^2-11+2=0
We add all the numbers together, and all the variables
(-5x)/5x^2+(-7x)/5x^2-9=0
We multiply all the terms by the denominator
(-5x)+(-7x)-9*5x^2=0
Wy multiply elements
-45x^2+(-5x)+(-7x)=0
We get rid of parentheses
-45x^2-5x-7x=0
We add all the numbers together, and all the variables
-45x^2-12x=0
a = -45; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-45)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-45}=\frac{0}{-90} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-45}=\frac{24}{-90} =-4/15 $
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