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-1/7x+5/6x=9
We move all terms to the left:
-1/7x+5/6x-(9)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 6x!=0We calculate fractions
x!=0/6
x!=0
x∈R
(-6x)/42x^2+35x/42x^2-9=0
We multiply all the terms by the denominator
(-6x)+35x-9*42x^2=0
We add all the numbers together, and all the variables
35x+(-6x)-9*42x^2=0
Wy multiply elements
-378x^2+35x+(-6x)=0
We get rid of parentheses
-378x^2+35x-6x=0
We add all the numbers together, and all the variables
-378x^2+29x=0
a = -378; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-378)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-378}=\frac{-58}{-756} =29/378 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-378}=\frac{0}{-756} =0 $
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