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-1/6x+4=5/2x
We move all terms to the left:
-1/6x+4-(5/2x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/6x-(+5/2x)+4=0
We get rid of parentheses
-1/6x-5/2x+4=0
We calculate fractions
(-2x)/12x^2+(-30x)/12x^2+4=0
We multiply all the terms by the denominator
(-2x)+(-30x)+4*12x^2=0
Wy multiply elements
48x^2+(-2x)+(-30x)=0
We get rid of parentheses
48x^2-2x-30x=0
We add all the numbers together, and all the variables
48x^2-32x=0
a = 48; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·48·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*48}=\frac{0}{96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*48}=\frac{64}{96} =2/3 $
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