-1/6(x-18)+.5(x+2)=x+4

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Solution for -1/6(x-18)+.5(x+2)=x+4 equation: 



-1/6(x-18)+.5(x+2)=x+4

We move all terms to the left:

-1/6(x-18)+.5(x+2)-(x+4)=0



Domain of the equation: 6(x-18)!=0

x∈R



We multiply parentheses

-1/6(x-18)+0.5x-(x+4)+1=0

We get rid of parentheses

-1/6(x-18)+0.5x-x-4+1=0

We multiply all the terms by the denominator


(0.5x)*6(x-18)-x*6(x-18)-4*6(x-18)+1*6(x-18)-1=0

We add all the numbers together, and all the variables

(+0.5x)*6(x-18)-x*6(x-18)-4*6(x-18)+1*6(x-18)-1=0

Wy multiply elements

-6x^2(x-24x(x+6x(x-1+(+0.5x)*6(x-18)=0

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