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-1/5x=2x+3
We move all terms to the left:
-1/5x-(2x+3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
-1/5x-2x-3=0
We multiply all the terms by the denominator
-2x*5x-3*5x-1=0
Wy multiply elements
-10x^2-15x-1=0
a = -10; b = -15; c = -1;
Δ = b2-4ac
Δ = -152-4·(-10)·(-1)
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{185}}{2*-10}=\frac{15-\sqrt{185}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{185}}{2*-10}=\frac{15+\sqrt{185}}{-20} $
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