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-1/5x-2=1/2x+7
We move all terms to the left:
-1/5x-2-(1/2x+7)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x+7)!=0We get rid of parentheses
x∈R
-1/5x-1/2x-7-2=0
We calculate fractions
(-2x)/10x^2+(-5x)/10x^2-7-2=0
We add all the numbers together, and all the variables
(-2x)/10x^2+(-5x)/10x^2-9=0
We multiply all the terms by the denominator
(-2x)+(-5x)-9*10x^2=0
Wy multiply elements
-90x^2+(-2x)+(-5x)=0
We get rid of parentheses
-90x^2-2x-5x=0
We add all the numbers together, and all the variables
-90x^2-7x=0
a = -90; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-90)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-90}=\frac{0}{-180} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-90}=\frac{14}{-180} =-7/90 $
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