-1/4a-4=7/a-3

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Solution for -1/4a-4=7/a-3 equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

(-1/4)*a-4 = 7/a-3 // - 7/a-3

(-1/4)*a-(7/a)-4+3 = 0

(-1/4)*a-7*a^-1-4+3 = 0

-1/4*a^1-7*a^-1-1*a^0 = 0

(-1/4*a^2-1*a^1-7*a^0)/(a^1) = 0 // * a^2

a^1*(-1/4*a^2-1*a^1-7*a^0) = 0

a^1

(-1/4)*a^2-a-7 = 0

(-1/4)*a^2-a-7 = 0

DELTA = (-1)^2-(-7*4*(-1/4))

DELTA = -6

DELTA < 0

a in { } 

a belongs to the empty set

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