-1/4(x-8)+(1/2)(x+2)=x+3

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Solution for -1/4(x-8)+(1/2)(x+2)=x+3 equation: 



-1/4(x-8)+(1/2)(x+2)=x+3

We move all terms to the left:

-1/4(x-8)+(1/2)(x+2)-(x+3)=0



Domain of the equation: 4(x-8)!=0

x∈R





Domain of the equation: 2)(x+2)!=0

x∈R



We add all the numbers together, and all the variables

-1/4(x-8)+(+1/2)(x+2)-(x+3)=0

We get rid of parentheses

-1/4(x-8)+(+1/2)(x+2)-x-3=0

We multiply parentheses ..

(+x^2+1/2*2)-1/4(x-8)-x-3=0

We calculate fractions


-x+((x^2+4xx)/16x^2+()/16x^2-3=0

We can not solve this equation

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