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-1/3x-5/12=1/4x+1
We move all terms to the left:
-1/3x-5/12-(1/4x+1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x+1)!=0We get rid of parentheses
x∈R
-1/3x-1/4x-1-5/12=0
We calculate fractions
(-240x^2)/144x^2+(-48x)/144x^2+(-36x)/144x^2-1=0
We multiply all the terms by the denominator
(-240x^2)+(-48x)+(-36x)-1*144x^2=0
Wy multiply elements
(-240x^2)-144x^2+(-48x)+(-36x)=0
We get rid of parentheses
-240x^2-144x^2-48x-36x=0
We add all the numbers together, and all the variables
-384x^2-84x=0
a = -384; b = -84; c = 0;
Δ = b2-4ac
Δ = -842-4·(-384)·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-84}{2*-384}=\frac{0}{-768} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+84}{2*-384}=\frac{168}{-768} =-7/32 $
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