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-1/3x+2=2x-1
We move all terms to the left:
-1/3x+2-(2x-1)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
-1/3x-2x+1+2=0
We multiply all the terms by the denominator
-2x*3x+1*3x+2*3x-1=0
Wy multiply elements
-6x^2+3x+6x-1=0
We add all the numbers together, and all the variables
-6x^2+9x-1=0
a = -6; b = 9; c = -1;
Δ = b2-4ac
Δ = 92-4·(-6)·(-1)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{57}}{2*-6}=\frac{-9-\sqrt{57}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{57}}{2*-6}=\frac{-9+\sqrt{57}}{-12} $
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