-1/3x+11/2=1/2(3-x)

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Solution for -1/3x+11/2=1/2(3-x) equation: 



-1/3x+11/2=1/2(3-x)

We move all terms to the left:

-1/3x+11/2-(1/2(3-x))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 2(3-x))!=0

x∈R



We add all the numbers together, and all the variables

-1/3x-(1/2(-1x+3))+11/2=0

We calculate fractions


(-4x(-)/(12x^2(-)+(-(1*3x)/(12x^2(-)+33x/(12x^2(-)=0



We calculate terms in parentheses: +(-4x(-)/(12x^2(-)+(-(1*3x)/(12x^2(-)+33x/(12x^2(-), so:

-4x(-)/(12x^2(-)+(-(1*3x)/(12x^2(-)+33x/(12x^2(-

We can not solve this equation

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