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-1/3n+5+2/9n=3
We move all terms to the left:
-1/3n+5+2/9n-(3)=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 9n!=0We add all the numbers together, and all the variables
n!=0/9
n!=0
n∈R
-1/3n+2/9n+2=0
We calculate fractions
(-9n)/27n^2+6n/27n^2+2=0
We multiply all the terms by the denominator
(-9n)+6n+2*27n^2=0
We add all the numbers together, and all the variables
6n+(-9n)+2*27n^2=0
Wy multiply elements
54n^2+6n+(-9n)=0
We get rid of parentheses
54n^2+6n-9n=0
We add all the numbers together, and all the variables
54n^2-3n=0
a = 54; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·54·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*54}=\frac{0}{108} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*54}=\frac{6}{108} =1/18 $
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