-1/3(9p-18)=p+12+6

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Solution for -1/3(9p-18)=p+12+6 equation: 



-1/3(9p-18)=p+12+6

We move all terms to the left:

-1/3(9p-18)-(p+12+6)=0



Domain of the equation: 3(9p-18)!=0

p∈R



We add all the numbers together, and all the variables

-1/3(9p-18)-(p+18)=0

We get rid of parentheses

-1/3(9p-18)-p-18=0

We multiply all the terms by the denominator


-p*3(9p-18)-18*3(9p-18)-1=0

Wy multiply elements

-3p^2(9-54p(9-1=0

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