-1/2z+2=3z

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Solution for -1/2z+2=3z equation: 



-1/2z+2=3z

We move all terms to the left:

-1/2z+2-(3z)=0



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R



We add all the numbers together, and all the variables

-3z-1/2z+2=0

We multiply all the terms by the denominator


-3z*2z+2*2z-1=0

Wy multiply elements

-6z^2+4z-1=0

a = -6; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·(-6)·(-1)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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