-1/2x=3/4x+1=12

Solution for -1/2x=3/4x+1=12 equation:

-1/2x=3/4x+1=12

We move all terms to the left:

-1/2x-(3/4x+1)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+1)!=0

x∈R


We get rid of parentheses

-1/2x-3/4x-1=0

We calculate fractions


(-4x)/8x^2+(-6x)/8x^2-1=0

We multiply all the terms by the denominator


(-4x)+(-6x)-1*8x^2=0

Wy multiply elements

-8x^2+(-4x)+(-6x)=0

We get rid of parentheses

-8x^2-4x-6x=0

We add all the numbers together, and all the variables

-8x^2-10x=0

a = -8; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-8)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-8}=\frac{20}{-16}
=-1+1/4
$