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-1/2p+3p=5
We move all terms to the left:
-1/2p+3p-(5)=0
Domain of the equation: 2p!=0We add all the numbers together, and all the variables
p!=0/2
p!=0
p∈R
3p-1/2p-5=0
We multiply all the terms by the denominator
3p*2p-5*2p-1=0
Wy multiply elements
6p^2-10p-1=0
a = 6; b = -10; c = -1;
Δ = b2-4ac
Δ = -102-4·6·(-1)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{31}}{2*6}=\frac{10-2\sqrt{31}}{12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{31}}{2*6}=\frac{10+2\sqrt{31}}{12} $
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