-1/2(6+4x)=1/3(9-3x)

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Solution for -1/2(6+4x)=1/3(9-3x) equation:



-1/2(6+4x)=1/3(9-3x)
We move all terms to the left:
-1/2(6+4x)-(1/3(9-3x))=0
Domain of the equation: 2(6+4x)!=0
x∈R
Domain of the equation: 3(9-3x))!=0
x∈R
We add all the numbers together, and all the variables
-1/2(4x+6)-(1/3(-3x+9))=0
We calculate fractions
(-3x(-)/(2(4x+6)*3(-3x+9)))+(-2x4/(2(4x+6)*3(-3x+9)))=0
We calculate terms in parentheses: +(-3x(-)/(2(4x+6)*3(-3x+9))), so:
-3x(-)/(2(4x+6)*3(-3x+9))
We add all the numbers together, and all the variables
-3x0/(2(4x+6)*3(-3x+9))
We multiply all the terms by the denominator
-3x0
We add all the numbers together, and all the variables
-3x
Back to the equation:
+(-3x)
We calculate terms in parentheses: +(-2x4/(2(4x+6)*3(-3x+9))), so:
-2x4/(2(4x+6)*3(-3x+9))
We multiply all the terms by the denominator
-2x4
We add all the numbers together, and all the variables
-2x^4
We do not support expression: x^4

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