-1/2(4y-8)=3y+y-2

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Solution for -1/2(4y-8)=3y+y-2 equation: 



-1/2(4y-8)=3y+y-2

We move all terms to the left:

-1/2(4y-8)-(3y+y-2)=0



Domain of the equation: 2(4y-8)!=0

y∈R



We add all the numbers together, and all the variables

-1/2(4y-8)-(4y-2)=0

We get rid of parentheses

-1/2(4y-8)-4y+2=0

We multiply all the terms by the denominator


-4y*2(4y-8)+2*2(4y-8)-1=0

Wy multiply elements

-8y^2(4+4y(4-1=0

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