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-1/2(12v-20)+4=-12-8v
We move all terms to the left:
-1/2(12v-20)+4-(-12-8v)=0
Domain of the equation: 2(12v-20)!=0We add all the numbers together, and all the variables
v∈R
-1/2(12v-20)-(-8v-12)+4=0
We get rid of parentheses
-1/2(12v-20)+8v+12+4=0
We multiply all the terms by the denominator
8v*2(12v-20)+12*2(12v-20)+4*2(12v-20)-1=0
Wy multiply elements
16v^2(1+24v(1+8v(1-1=0
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