-1/(3)k+6=9

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Solution for -1/(3)k+6=9 equation: 



-1/(3)k+6=9

We move all terms to the left:

-1/(3)k+6-(9)=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R



We add all the numbers together, and all the variables

-1/3k-3=0

We multiply all the terms by the denominator


-3*3k-1=0

Wy multiply elements

-9k-1=0

We move all terms containing k to the left, all other terms to the right

-9k=1

k=1/-9

k=-1/9

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