-1/(2x-2)-1/(3x+3)=0

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Solution for -1/(2x-2)-1/(3x+3)=0 equation: 



-1/(2x-2)-1/(3x+3)=0



Domain of the equation: (2x-2)!=0

We move all terms containing x to the left, all other terms to the right

2x!=2

x!=2/2

x!=1

x∈R





Domain of the equation: (3x+3)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-3

x!=-3/3

x!=-1

x∈R



We calculate fractions


(-1*(3x+3))/((2x-2)*(3x+3))+(-1*(2x-2))/((2x-2)*(3x+3))=0



We calculate terms in parentheses: +(-1*(3x+3))/((2x-2)*(3x+3)), so:

-1*(3x+3))/((2x-2)*(3x+3)

We multiply all the terms by the denominator


-1*(3x+3))

Back to the equation:

+(-1*(3x+3)))





We calculate terms in parentheses: +(-1*(2x-2))/((2x-2)*(3x+3)), so:

-1*(2x-2))/((2x-2)*(3x+3)

We multiply all the terms by the denominator


-1*(2x-2))

Back to the equation:

+(-1*(2x-2)))

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