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-1.5y^2=-3
We move all terms to the left:
-1.5y^2-(-3)=0
We add all the numbers together, and all the variables
-1.5y^2+3=0
a = -1.5; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-1.5)·3
Δ = 18
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18}=\sqrt{9*2}=\sqrt{9}*\sqrt{2}=3\sqrt{2}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{2}}{2*-1.5}=\frac{0-3\sqrt{2}}{-3} =-\frac{3\sqrt{2}}{-3} =-\frac{\sqrt{2}}{-1} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{2}}{2*-1.5}=\frac{0+3\sqrt{2}}{-3} =\frac{3\sqrt{2}}{-3} =\frac{\sqrt{2}}{-1} $
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