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-1.5x^2=-3.6-2.4x
We move all terms to the left:
-1.5x^2-(-3.6-2.4x)=0
We add all the numbers together, and all the variables
-1.5x^2-(-2.4x-3.6)=0
We get rid of parentheses
-1.5x^2+2.4x+3.6=0
a = -1.5; b = 2.4; c = +3.6;
Δ = b2-4ac
Δ = 2.42-4·(-1.5)·3.6
Δ = 27.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{27.36}}{2*-1.5}=\frac{-2.4-\sqrt{27.36}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{27.36}}{2*-1.5}=\frac{-2.4+\sqrt{27.36}}{-3} $
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