-1-5(b+3)=-(1-2b)-8b

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Solution for -1-5(b+3)=-(1-2b)-8b equation: 



-1-5(b+3)=-(1-2b)-8b

We move all terms to the left:

-1-5(b+3)-(-(1-2b)-8b)=0

We add all the numbers together, and all the variables

-5(b+3)-(-(-2b+1)-8b)-1=0

We multiply parentheses

-5b-(-(-2b+1)-8b)-15-1=0



We calculate terms in parentheses: -(-(-2b+1)-8b), so:

-(-2b+1)-8b

We add all the numbers together, and all the variables

-8b-(-2b+1)

We get rid of parentheses

-8b+2b-1

We add all the numbers together, and all the variables

-6b-1

Back to the equation:

-(-6b-1)



We add all the numbers together, and all the variables

-5b-(-6b-1)-16=0

We get rid of parentheses

-5b+6b+1-16=0

We add all the numbers together, and all the variables

b-15=0

We move all terms containing b to the left, all other terms to the right

b=15

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