-1-2(2b-5)=3+b

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Solution for -1-2(2b-5)=3+b equation: 



-1-2(2b-5)=3+b

We move all terms to the left:

-1-2(2b-5)-(3+b)=0

We add all the numbers together, and all the variables

-2(2b-5)-(b+3)-1=0

We multiply parentheses

-4b-(b+3)+10-1=0

We get rid of parentheses

-4b-b-3+10-1=0

We add all the numbers together, and all the variables

-5b+6=0

We move all terms containing b to the left, all other terms to the right

-5b=-6

b=-6/-5

b=1+1/5

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