-1,7-0,1(2z+1)=0,2(z-3)

Solution for -1,7-0,1(2z+1)=0,2(z-3) equation:

-1.7-0.1(2z+1)=0.2(z-3)

We move all terms to the left:

-1.7-0.1(2z+1)-(0.2(z-3))=0

We multiply parentheses

-0.2z-(0.2(z-3))-0.1-1.7=0


We calculate terms in parentheses: -(0.2(z-3)), so:

0.2(z-3)

We multiply parentheses

0.2z-0.6

Back to the equation:

-(0.2z-0.6)


We add all the numbers together, and all the variables

-0.2z-(0.2z-0.6)-1.8=0

We get rid of parentheses

-0.2z-0.2z+0.6-1.8=0

We add all the numbers together, and all the variables

-0.4z-1.2=0

We move all terms containing z to the left, all other terms to the right

-0.4z=1.2

z=1.2/-0.4

z=-2+0.4/0.4