-1+2(t+3)=5-(t-3)

Solution for -1+2(t+3)=5-(t-3) equation:

-1+2(t+3)=5-(t-3)

We move all terms to the left:

-1+2(t+3)-(5-(t-3))=0

We multiply parentheses

2t-(5-(t-3))+6-1=0


We calculate terms in parentheses: -(5-(t-3)), so:

5-(t-3)

determiningTheFunctionDomain
-(t-3)+5

We get rid of parentheses

-t+3+5

We add all the numbers together, and all the variables

-1t+8

Back to the equation:

-(-1t+8)


We add all the numbers together, and all the variables

2t-(-1t+8)+5=0

We get rid of parentheses

2t+1t-8+5=0

We add all the numbers together, and all the variables

3t-3=0

We move all terms containing t to the left, all other terms to the right

3t=3

t=3/3

t=1