-1(x-2)(x+2)=0

Solution for -1(x-2)(x+2)=0 equation:

Simplifying
-1(x + -2)(x + 2) = 0

Reorder the terms:
-1(-2 + x)(x + 2) = 0

Reorder the terms:
-1(-2 + x)(2 + x) = 0

Multiply (-2 + x) * (2 + x)
-1(-2(2 + x) + x(2 + x)) = 0
-1((2 * -2 + x * -2) + x(2 + x)) = 0
-1((-4 + -2x) + x(2 + x)) = 0
-1(-4 + -2x + (2 * x + x * x)) = 0
-1(-4 + -2x + (2x + x2)) = 0

Combine like terms: -2x + 2x = 0
-1(-4 + 0 + x2) = 0
-1(-4 + x2) = 0
(-4 * -1 + x2 * -1) = 0
(4 + -1x2) = 0

Solving
4 + -1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x2 = 0 + -4
-1x2 = 0 + -4

Combine like terms: 0 + -4 = -4
-1x2 = -4

Divide each side by '-1'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}