-1(8x2-2)=3+10(1-3x)

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Solution for -1(8x2-2)=3+10(1-3x) equation:



-1(8x^2-2)=3+10(1-3x)
We move all terms to the left:
-1(8x^2-2)-(3+10(1-3x))=0
We add all the numbers together, and all the variables
-1(8x^2-2)-(3+10(-3x+1))=0
We calculate terms in parentheses: -(3+10(-3x+1)), so:
3+10(-3x+1)
determiningTheFunctionDomain 10(-3x+1)+3
We multiply parentheses
-30x+10+3
We add all the numbers together, and all the variables
-30x+13
Back to the equation:
-(-30x+13)
We get rid of parentheses
-1(8x^2-2)+30x-13=0
We add all the numbers together, and all the variables
30x-1(8x^2-2)-13=0
We move all terms containing x to the left, all other terms to the right
30x-1(8x^2-2)=13

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