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-1(2x-3)+4=5x+2(3x+5)
We move all terms to the left:
-1(2x-3)+4-(5x+2(3x+5))=0
We calculate terms in parentheses: -(5x+2(3x+5)), so:We get rid of parentheses
5x+2(3x+5)
We multiply parentheses
5x+6x+10
We add all the numbers together, and all the variables
11x+10
Back to the equation:
-(11x+10)
-1(2x-3)-11x-10+4=0
We add all the numbers together, and all the variables
-11x-1(2x-3)-6=0
We move all terms containing x to the left, all other terms to the right
-11x-1(2x-3)=6
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