-1(1x-1)+10=-3(x-2)

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Solution for -1(1x-1)+10=-3(x-2) equation: 



-1(1x-1)+10=-3(x-2)

We move all terms to the left:

-1(1x-1)+10-(-3(x-2))=0

We add all the numbers together, and all the variables

-1(x-1)-(-3(x-2))+10=0



We calculate terms in parentheses: -(-3(x-2)), so:

-3(x-2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

-1(x-1)+3x-6+10=0

We add all the numbers together, and all the variables

3x-1(x-1)+4=0

We move all terms containing x to the left, all other terms to the right

3x-1(x-1)=-4

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