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-0.75x^2+1.75x+6=0
a = -0.75; b = 1.75; c = +6;
Δ = b2-4ac
Δ = 1.752-4·(-0.75)·6
Δ = 21.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.75)-\sqrt{21.0625}}{2*-0.75}=\frac{-1.75-\sqrt{21.0625}}{-1.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.75)+\sqrt{21.0625}}{2*-0.75}=\frac{-1.75+\sqrt{21.0625}}{-1.5} $
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