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-.4x^2+3x+12=-.2x+9
We move all terms to the left:
-.4x^2+3x+12-(-.2x+9)=0
We add all the numbers together, and all the variables
-.4x^2+3x-(-0.2x+9)+12=0
We add all the numbers together, and all the variables
-0.4x^2+3x-(-0.2x+9)+12=0
We get rid of parentheses
-0.4x^2+3x+0.2x-9+12=0
We add all the numbers together, and all the variables
-0.4x^2+3.2x+3=0
a = -0.4; b = 3.2; c = +3;
Δ = b2-4ac
Δ = 3.22-4·(-0.4)·3
Δ = 15.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{15.04}}{2*-0.4}=\frac{-3.2-\sqrt{15.04}}{-0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{15.04}}{2*-0.4}=\frac{-3.2+\sqrt{15.04}}{-0.8} $
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