-(z+7)+(2z+1)=2(z+1)

Solution for -(z+7)+(2z+1)=2(z+1) equation:

Simplifying
-1(z + 7) + (2z + 1) = 2(z + 1)

Reorder the terms:
-1(7 + z) + (2z + 1) = 2(z + 1)
(7 * -1 + z * -1) + (2z + 1) = 2(z + 1)
(-7 + -1z) + (2z + 1) = 2(z + 1)

Reorder the terms:
-7 + -1z + (1 + 2z) = 2(z + 1)

Remove parenthesis around (1 + 2z)
-7 + -1z + 1 + 2z = 2(z + 1)

Reorder the terms:
-7 + 1 + -1z + 2z = 2(z + 1)

Combine like terms: -7 + 1 = -6
-6 + -1z + 2z = 2(z + 1)

Combine like terms: -1z + 2z = 1z
-6 + 1z = 2(z + 1)

Reorder the terms:
-6 + 1z = 2(1 + z)
-6 + 1z = (1 * 2 + z * 2)
-6 + 1z = (2 + 2z)

Solving
-6 + 1z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-6 + 1z + -2z = 2 + 2z + -2z

Combine like terms: 1z + -2z = -1z
-6 + -1z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-6 + -1z = 2 + 0
-6 + -1z = 2

Add '6' to each side of the equation.
-6 + 6 + -1z = 2 + 6

Combine like terms: -6 + 6 = 0
0 + -1z = 2 + 6
-1z = 2 + 6

Combine like terms: 2 + 6 = 8
-1z = 8

Divide each side by '-1'.
z = -8

Simplifying
z = -8